Question 254150
Let the number of cows = x
Let the number of chickens = y
Total number of heads = x+y
Every cow has 4 legs and every chicken has 2 legs
Total number of legs = 4x+2y
Given, the number of legs was 16 more than twice the number of heads.
        4x+2y = 2(x+y)+16
        4x+2y = 2x+2y+16
           2x = 16
            x = 8
Therefore the number of cows = 8