Question 253925
please help me: {{{2y/y-1 = 5/y + 10-8y/y^2-y}}}

First we simplify:

Remember 2y/y = 2 and y/y^2 = 8/y.

So we have:

2 - 1 = 5/y + 10 - 8/y - y

Now multiply both sides by y:

2y - y = 5 + 10y - 8 - y^2

So we have:

y^2 - 9y + 3 = 0

Solve for y.