Question 253925
2y/(y-1) = 5/y + 10-8y/(y^2-y)
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Multiply thru by y(y-1) to get:
2y(y) = 5(y-1) + 10y(y-1) - 8y
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2y^2 = 5y-1 + 10y^2 - 10y - 8y
2y^2 = -13y + 10y^2
8y^2 - 13y = 0
y(8y - 13) = 0
y = 0 or y = 13/8
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Cheers,
Stan H.