Question 253873
We have  the following:
(i) {{{log_81(80)}}}
By change of base, we get
(ii) {{{log(80)/log(81)}}}
(iii) {{{Log(80) = log(8*10) = log(2^3*10) = 3log(2) + 1}}}
(iv) {{{log(81) = log(3^4)}}} = {{{log(3^4) = 4log(3)}}}
substituting (iii) and (iv) into (ii) we get
(v) {{{(3log(2) + 1)/(4log(3))}}}
 We were given
a=log_10(2), and b= log_10(3).
Substituting, we get
{{{(3a + 1)/(4b)}}}