Question 253823
FIrst create a rectangle with verticies A (0,0); B (3,0) ; C(3,2) ; D(0,2)
We can write equations passing through AC and BD using slope formula which is
{{{m = (y2-y1) / (x2-x1)}}}
step 1 find slope of AC
{{{m = (2-0) / (3-0)}}} = 2/3
step 2 - find slope of BD
{{{m = (2-0) /(02-3)}}} = -2/3
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We can find equations for AC and BD as
AC: Y = (2/3)x +  0
BD: Y = (-2/3)x + 2
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we have 2 lines not four that pass through the verticies ABCD.
We notice that the slopes are the same one + and one -.
I don't see four.