Question 253818
FIrst we are given 2 roots:
{{{2+3i}}}
and
{{{ sqrt(7)}}}.
The other 2 roots are
{{{2-3i}}}
and
{{{-sqrt(7)}}}
These are both conjugates.
So, we have a polynomial expressed as
{{{(x-(2+3i))(x-(2-3i))(x-sqrt(7))(x+sqrt(7))}}}
this can be simplified to
{{{(x^2-4x + 13)(x^2-7)}}}
and then to
{{{x^4-4x^3+6x-91}}}