Question 253657
The equation of the given line is x+4y = 7
The slope of the given line = -(coefficient of x)/(coefficient of y)=-1/4
The slope of a line perpendicular to the given line = 4
Therefore, the equation of a line that is perpendicular to x + 4y=7 and 
through point(1,1) is y-1 = 4(x-1)
                      y-1 = 4x-4
                        y = 4x-3