<PRE><B>Question 253766</B>
Let the speed of the first car be x km/h
Then the speed of the second car = x+12
Time taken by tne first car to travel 93kms = 93/x
Time taken by tne second car to travel 111 kms = 111/(x+12)
Given, both times are equal.
                93/x = 111/(x+12)
           93*(x+12) = 111x
            93x+1116 = 111x
                1116 = 111x-93x
                1116 = 18x
                   x = 1116/18
                   x = 62
So the speed of the first car is 62 kms/h
and the speed of the second car is 62+12 = 74 kms/h </PRE>