Question 32036
m + 3 divided by m - 3 < or equal to 2, D = {Reals}

It can be written as 

(m + 3)/ m - 3 <= 2

multiply both sides by m-3 and we get

m + 3 <= 2m - 6

put together like variables and we get

0 <= 2m - m -6 - 3 

 0 <= m - 9

since D = real 

therefore m-9 >= 0

subtract 9 from both sides,,we get
 
m >= 9 

hope this will help you 

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