<PRE><B>Question 253628</B>


{{{3x-8y=42}}} Start with the given equation.



{{{-8y=42-3x}}} Subtract {{{3x}}} from both sides.



{{{-8y=-3x+42}}} Rearrange the terms.



{{{y=(-3x+42)/(-8)}}} Divide both sides by {{{-8}}} to isolate y.



{{{y=((-3)/(-8))x+(42)/(-8)}}} Break up the fraction.



{{{y=(3/8)x-21/4}}} Reduce.



So the equation {{{y=(3/8)x-21/4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=3/8}}} and the y-intercept is {{{b=-21/4}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-\frac{21}{4}\right)]
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