Question 253555
Both triangles will be in quad II.

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Quad II, angle x:
Label the y-axis (vertical leg)  = 3
Label the x-axis (horizontal leg) = -4
Label the hypotenuse = 5
sin(x) = 3/5
cos(x) =-4/5
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Quad II, angle y:
Label the y-axis (vertical leg)  = 12
Label the x-axis (horizontal leg) = -5
Label the hypotenuse = 13
siny = 12/13
cosy = -5/13
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We want sin(x-y), so we need the formula
{{{sin(x-y) = sinxcosy - sinycosx}}}
we substitute our information in as:
{{{sin(x-y) = (3/5)(-5/13) - (12/13)(-4/5)}}}
{{{sin(x-y) = -15/169 + 48/169}}}
{{{sin(x-y) = 33/169}}}