Question 253556
{{{8y^2-10y+3=0}}}
By factoring, we get:
{{{(2x-1)(4X-3) = 0}}}
Solving each, we get
{{{2x-1 = 0}}}
{{{2x = 1}}}
X = 1/2
OR
{{{(4x-3)=0}}}
{{{4x = 3}}}
x = 3/4.