Question 253500
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I think you mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3x\ -\ 1}{x\ -\ 8}\ -\ 4\ \leq\ 0]


In which case you should have written:


((3x - 1)/(x - 8)) - 4 <= 0


And then there would have been no confusion.


On the other hand, you might have meant


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3x\ -\ 1}{x\ -\ 8}\ -\ (-4)\ \leq\ 0]


because you said "subtract -4", in which case you should have written:


((3x - 1)/(x - 8)) - (-4) <= 0


Presuming the first rendering is correct and presuming, though you didn't say so, that you want to solve for *[tex \Large x], proceed as follows:


Add 4 to both sides of the inequality:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3x\ -\ 1}{x\ -\ 8}\ \leq\ 4]


Multiply both sides by *[tex \Large x\ -\ 8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ -\ 1\ \leq\ 4x\ -\ 32]


Add *[tex \Large -4x] and 1 to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -x\ \leq\ -31]


Multiply both sides by -1 and reverse the sense of the inequality:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ \geq\ 31]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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