Question 253518
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Yes, I can.


Remember that distance equals rate times time, or *[tex \Large d\ =\ rt].


But that means that time is equal to distance divided by rate, or *[tex \Large t\ =\ \frac{d}{r}]


With that in mind, let's take a look at your second equation.  The right hand side of your equation is 30, which I take to mean the given 30 minutes.  That is an amount of time.  Therefore, the left hand side of your equation should be the sum of two amounts of time, namely the amount of time spent walking plus the amount of time spent jogging.  You have <i>multiplied</i> the walking rate (0.05) times the distance walked (*[tex \Large x]) and the jogging rate (0.1) times the distance jogged (*[tex \Large y]).  You should be <i>dividing</i> the distance by the rate, thus:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x}{0.05}\ +\ \frac{y}{0.1}\ =\ 30]


Now solve the system using your correctly constructed first equation.  Write back if you need more help.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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