Question 253506
(i) {{{x^(1/6)*y^(1/3)*z^(1/4)}}}
first get a common denominator as 12 and change the numerators
(ii) {{{x^(2/12)*y^(4/12)*z^(3/12)}}})
Nw we can write this as information to the 1/12 power as:
(iii) {{{ (x^(2)*y^(4)*z^(3))^(1/12)}}}