Question 31839
y=x^2+1
Substitute y=5x-3 in the above equation:
5x-3=x^2+1
=>x^2-5x+4=0
=>(x-4)(x-1)=0
=>x=4 or x=1
........
y=2x+5
Substitute y=12/5 in the above equation:
=>12/5=2x+5
=>10x+25=12
=>10x=-13
=>x=-13/10
Let me know if the steps need more detail