Question 253481
let the no.s be 10n, 10(n+1), 10(n+2), 10(n+3)

given their sum is 300

so 10(n+n+1+n+2+n+3)=300

=>  10(4n+6)=300
=>    4n+6=30
=>    4n=24

so   n=6

so the least number is 10n i.e., 60
ans: E