Question 253445
A taxi left Los Angeles at 7:50 am travelling 50 kph. At 9 am, an express train travelling 110 kph left the same spot travelled by the taxi.
Let the taxi and the train meet x hours after 9AM.
Distance travelled by the taxi = (x+1 10/60)*50
Distance travelled by the train = x*110
When they meet, the two distances are equal
         (x+7/6)*50 = 110x
          50x+350/6 = 110x
               175/3= 60x
                  x = 175/180 hours
                  x = (175/180)*60 minutes
                  x = 175/3 minutes
                  x = 58 min 20 sec
Therefore they will meet at 9h 58m 20s