Question 31988
3x^2-2=4x
=>3x^2-4x-2=0
Apply quadratic formula:
x=[4+sqrt(16-24)/6] or x==[4-sqrt(16-24)/6]
=>x==[4+sqrt(-8)/6] or x==[4-sqrt(-8)/6]
=>x=[2+sqrt(2)i]/3 or x==[2-sqrt(2)i]/3