Question 32058
Assume x ounces of 5% solution is to be mixed.
Total volume of the mix=60 ounces; so, 60-x ounces of pure (100%) solution is to be mixed to kill algae in the pool;
Thus, 5% of x + 100% of (60-x) = 15% of 60
=> .05x+(60-x)  = .15*60
=>60-.95x=9
=>.95x=60-9
=>.95x=51
=>x=51/.95=53.68
So, about 54 ounces of 5% solution is to be mixed with 6 ounces of pure solution.  For this type of questions, usually the numbers do not come so odd.