Question 253320
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-1,1\right)]. So this means that {{{x[1]=-1}}} and {{{y[1]=1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(1,2\right)].  So this means that {{{x[2]=1}}} and {{{y[2]=2}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(2-1)/(1--1)}}} Plug in {{{y[2]=2}}}, {{{y[1]=1}}}, {{{x[2]=1}}}, and {{{x[1]=-1}}}



{{{m=(1)/(1--1)}}} Subtract {{{1}}} from {{{2}}} to get {{{1}}}



{{{m=(1)/(2)}}} Subtract {{{-1}}} from {{{1}}} to get {{{2}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(-1,1\right)] and *[Tex \LARGE \left(1,2\right)] is {{{m=1/2}}}