Question 253285
Let {{{h}}} = hundreds digit
Let {{{t}}} = tens digit
Let {{{u}}} = units digit
The actual number must be
{{{100h + 10t + u}}}
given:
(1){{{t = 5u - 3}}}
(2) {{{3*(h + t + u) = 4h + 2}}}
The number with the digits reversed would be
{{{100u + 10t + h}}}
(3) {{{100u + 10t + h = 100h + 10t + u - 594}}}
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I have the 3 equations and I just need to tidy them up
and solve for {{{h}}},{{{t}}}, and {{{u}}}
I'll leave this for you