Question 253168
We know the sum must end in 4
74+47 ends in 1
31+13 ends in 4 but has only two digits
86+68 ends in 4 and has three digits sum is 154
47+74 ends in 1 same as A)
95+59 ends in 4 and has three digits sum is 154
A,B, C and D are all unique so 95 and 59 can't use the 5 again in the sum
So the only acceptable answer is 86 and 68.