Question 32012
Let the ten digit number be x
<pre><b>Let the one digit number be y
x+y=5
y=5-x (subsitution)
WHen the digit is reversed:
10y+x=10x+y+9
Subsitute for y:
10(5-x)+x=10x+5-x+9
50-10x+x=10x+14-x
50-9x=9x+14
18x=36
x=2
y=5-2
y=3
Hence, the 10 digit number is 2 and the one digit number is 3.
The number is 23.
Paul.