Question 253190
Draw your parallelogram with sides 8 and 14 with angle of 60 degrees with the 60 angle at the base on the left.
If one angle is 60 the opposite angle is also 60.
The remaining angles are 120 each.
Now draw the height (altitude) from the 120 angle to the base .
We now have a right triangle with angles 30 60 90. We know that the sides in a 30 60 90 triangle are  proportioned 1:sqrt(3):2  
Now since the hypotenuse is 8 the triangles proportions are multiplied by 4.
so the altitude is 4sqrt(3)
We are not told where the 60 degree angle is.
I choose to make the base 14 and the altitude is 4sqrt
So the area is base  times height which is 14*4sqrt(3)=64sqrt(3)
If the base is 8 then the height is 7sqrt(3) and the area is 8*7sqrt(3) or 56sqrt(3)