Question 253107
The given equations are,
               3x-2y= -19 ...(1)
               2y= 2x+16  ...(2)
   Sustituting in (1), we get
               3x-(2x+16) = -19
               3x-2x-16   = -19
                        x = -19+16
                        x = -3 
Put x=-3 in(1). 3*(-3)-2y =-19
                    -9-2y = -19
                      -2y = -19+9
                        y = (-10)/(-2) 
                        y = 5
Therefore the solution is x = -3 and y = 5