Question 31999
Solve:
{{{sqrt(7x+29) = x+3}}} Square both sides of the equation.
{{{7x+29 = x^2+6x+9}}} rewrite in standard quadratic form.
{{{x^2-x-20 = 0}}} Factor.
{{{(x+4)(x-5) = 0}}} Apply the zero products principle.
{{{x+4 = 0}}} and/or {{{x-5 = 0}}}
If {{{x+4 = 0}}} then {{{x= -4}}}
If {{{x-5 = 0}}} then {{{x = 5}}}
The roots are both real:
x = -4
x = 5