Question 31986
[2x/(x+5)]/[x^2/(x-1)]
= Invert the denominator and multiply to get:
[2x/(x+5)]*[(x-1)/x^2]
Cancel the factor "x" common to numerator and denominator, as follows:
[2/(x+5)]*[(x-1)/x]
Multiply to get:
[2x-1]/[x^2+5x]
Cheers,
Stan H.