<PRE><B>Question 253037</B>
In general,


probability of A and B is equal to probability of A times probability of B.
probability of A or B is equal to probability of A plus probability of B.


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probability of getting a position at company A is equal to .4
probability of getting a position at company B is equal to .3
probability of getting a position at company C is equal to .6

probability of NOT getting a position at company A is equal to 1 - .4 = .6
probability of NOT getting a position at company B is equal to 1 - .3 = .7
probability of NOT getting a position at company C is equal to 1 - .6 = .4


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a. what is the probability that the person will recieve job offers from all three companies.


probability of getting a job offer from all 3 companies is equal to:
probability of getting a job offer from company A times:
probability of getting a job offer from company B times:
probability of getting a job offer from company C.


p(A) * p(B) *p(C) =  .4 * .3 * .6 = .072


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b.what is the probability that the person will recieve a job offer from Company B only?


probability of getting a job offer from company B only is equal to:
probability of getting a job offer from company B times:
probability of NOT getting a job offer from company A times:
probability of NOT getting a job offer from company C.


p(B) * p(!A) * p(!C) =  .3 * .6 * .4 = .072


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C. what is the probability that the person will recieve exactly one job offer from the three companies?


the probability of getting a job offer from only one company is equal to:
the probability of getting a job offer from A and not B and not C, plus:
the probability of getting a job offer from B and not A and not C, plus:
the probability of getting a job offer from C and not A and not B.






p(A) * p(!B) * p(!C) = .4 * .7 * .4 = .112
p(B) * p(!A) * p(!C) = .3 * .6 * .4 = .072
p(C) * p(!A) * p(!B) = .6 * .6 * .7 = .252


total probability = .112 + .072 + .252 = .436






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