Question 253008
how many gallons of a mixture containing 80% alcohol should be added to 6 gallons of 25% solution to give 30% solution?
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6*0.25 + x*0.8 = (6+x)*0.3
1.5 + 0.8x = 1.8 + 0.3x
0.5x = 0.3
x = 0.6 gallons added