Question 252957
Here is the original equation:
{{{x^2+6x-3=0}}}
We have to solve by the quadratic
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a = 1, b = 6 and c =-3.
{{{x = (-6 +- sqrt( 6^2-4*1*(-3) ))/(2*(1)) }}}

we get x ~ .4641 and x ~ -6.4641