Question 250347
Parabola have the equation:
{{{Y = a(x-h)^2 + k}}}
where h,k is the vertex. We are given (0,3) as well as (-4, -45). Putting all of this in, we can find a as:
{{{-45 = a*(-4-0)^2 + 3}}}
{{{-45 = 16a + 3}}}
{{{-48 = 16a}}}
{{{a = -3}}}
The equation is
{{{Y = -3(x-0)^2 + 3}}}
or simply
{{{Y = -3x^2 + 3}}}