Question 252948
Here is the original problem:
{{{Ax + 3y = 5}}}
with coordinate (2,1).
substitute X and Y into the equation to get
{{{2A + 3(1) = 5}}}
{{{2A = 2}}}
{{{A = 1}}}
So, the equation should be:
x + 3Y = 5.
Hope that is what you were looking for.