<PRE><B>Question 250461</B>
We reduce length and width by the same amount to get
(20-X) and (23-x). Now the area is reduced by 120, so,
{{{460 - (20-X)(23-X) = 120}}}
foiling the left gives us
{{{460 - (x^2 - 43X + 460) = 120}}}
{{{-x^2 + 43X - 120 = 0 }}}
or
{{{x^2 - 43X + 120 = 0 }}}
by factoring, we get
{{{(x-3)(x-40) = 0}}}
X = 3 or X = 40.
Since 40 is too big,
 we are left with X = 3.
The new rectangle dimensions are:
17 x 20</PRE>