Question 250517
I think you want to simplify the following:
{{{(32c^2-2) / (4c+1)}}}
factor the numerator:
2(16C^2-1)
notice that is can be factored as difference of two squares. So we get
{{{2(4c+1)(4c-1)}}}
putting with the denominator, we get
{{{2(4c+1)(4c-1)}}} / {{{4c+1}}}
reducing the 4c+1, we get
2(4c-1)
8c-2