Question 250600
here is the original equation
{{{SQRT( -4*SQRT( 36 *cos(0))/(4*sin(90))-144+(5*5*5)) -16i/2}}}
One part at a time
the numerator is: 
{{{-4*SQRT( 36 *cos(0)) = -4*sqrt(36*1)}}} = -24
the denominator is: 
{{{4*sin(90) = 4*1}}} = 4
numerator over denominator is: 
{{{-24/4 = -6}}}
So, we have
{{{sqrt(-6 -144 + 125) = sqrt(-25)}}} = 5i.
Now,
5i -16pi/2 is the answer.