<PRE><B>Question 252874</B>
a speed boat traveling 60 kph left the port 5 minutes after a fishing boat sailed.
 If it overtakes the fishing boat after two hours, find the rate of the fishing boat.
:
Let s = the rate of the fishing boat
:
When the faster boat overtakes the slower boat they will have traveled the same distance.
Write a distance equation from this fact; dist = speed * time
change 5 min to hrs. 5/60 = .0833 hrs
Slow boat travel time = 2.0833 hrs
:
slow boat dist = fast boat dist
2.0833s = 2(60)
2.0833s = 120
s = {{{120/2.0833}}}
s = 57.6 km/hr speed of the slow boat
;
;
Check solution by finding the dist
2.0833 * 57.6 = 120 mi
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