Question 252827
let n= the first integer and n+1= the second
n^2+(n+1)^2=130
n^2+n^2+2n+1=130
2n^2+2n=129
there are no integer roots
Something is wrong with problem.
*[invoke quadratic "n", 2, 2, -129 ]
perhaps you mean consecutive even or consecutive odd
first =n second n+2
n^2+(n+2)^2=130
*[invoke quadratic "n",2, 4, -126 ]
that does work
we discard the negative answer -9
7^2+9^2
49 +81=130