Question 252804
Using log base 10

{{{ log 5^(x+2) = log 8.5}}}
{{{ (x+2)* log 5 = log 8.5}}}
{{{ (x+2)= log (8.5)/log 5}}}
{{{ x= (log (8.5)/log 5)-2}}}
{{{x= -0.67}}} 2 d.p.
|
{{{x* log 6.5= (4x-10)*log 8.4 }}}
{{{x= (4x-10)*log 8.4/log 6.5 }}}
{{{x= (4x-10)*1.137 }}}
{{{x= (4.548x-11.37)}}}
{{{11.37= (3.548x)}}}
{{{3.2046 = x}}} 4.dp.

All a bit messy. There probably is a better way of doing it.