Question 252802
4x^2 – 7x – 2 = 0  add 2 to each side
4x^2-7x=2  divide each term by 4
x^2-(7/4)x=1/2  take half of the x coefficient and square it and we get 49/64 and add to each side:

x^2-(7/4)x+49/64=32/64+49/64=81/64
(x-7/8)^2=81/64  take square root of each side
x-7/8=+or-9/8
x=7/8+or-9/8
x=-2/8=-1/4
and
x=16/8=2

The answer is "yes"

Hope this helps---ptaylor