<PRE><B>Question 252791</B>
a + b + c = 105


a,b,c represent the amount of peaches in bags A, B, and C.


b = 4*a; (bag B has 4 times the peaches in bag A).


c = 2 * (a + b); (bag C contains 2 times the amount in bags A and B).


since b = 4*a, then:


c = 2 * (a + b) becomes:


c = 2 * (a + 4*a).


remove parentheses to get:


c = 2*a + 8*a = 10*a


we have:


b = 4*a
c = 10*a


a + b + c = 105 becomes:


a + 4*a + 10*a = 105 which becomes:


15*a = 105


solve for a to get:


a = 105/15 = 7


b = 4*a = 4 * 7 = 28


c = 10*a = 10*7 = 70


70 + 28 + 7 = 105 (this is good).


b = 2 * (a + b) = 2 * (7 + 28) = 2 * 35 = 70 (this is also good).


You have confirmed that:


bag A contains 7 peaches
bag B contains 28 peaches
bag C contains 70 peaches


Your answer is bag C contains 70 peaches which is selection D.





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