Question 252753
ms.berger has two investments. one has 8% annual interest rat, and the other investment has 9.5%.
 she invests 37,000, part at 8% and the rest at 9.5% annual interest rate.
 the 9.5% investment provides $452.5 more income than 8% investment.
 how much is invested at each rate?
:
Let x = amt invested at 9.5%
The total was given as 37000, therefore
(37000-x) = amt invested at 8%
:
Int at 9.5% - Int at 8% = $452.5
.095x - .08(37000-x) = 452.50
.095x - 2960 + .08x = 452.50
.095x + .08x = 452.50 + 2960
.175x = 3412.5
x = {{{3412.5/.175}}}
x = $19,500 invested at 9.5%
:
I'll let you find how much invested at 8%