Question 31903
{{{ 36x^4y^2 - 49z^4 }}}
this is the difference of two squares and follows the form:
{{{ x^2-y^2 = (x-y)(x+y) }}}
find the square root of each term
{{{ (6x^2y-7z^2)(6x^2y+7z^2) }}}
This is as far as it can be factored




Next
{{{ x^2 -5x -14 }}}
With this, as yourself what two numbers, when multiplied give you 14, but when added or subtracted give you 5.
The answer is 7 and 2.
{{{ (x-7)(x+2) }}}
The have opposite signs because the 14 is negative.  And because the middle term is also negative, the larger of the two values has to be the negative one.