Question 252676
WE have two functions:
(i) f(x)=3x-6
(ii)g(x)=x-2
Now, F(x) / g(x) will be
(iii) 3x-6 / (x-2)
At this point we must look at domain. We have variables in the denominator. Set the denominator = 0 and solve for x.
x-2 = 0 - - > x = 2 is the restriction on the domain.
Back to the fraction . . .
We can factor the numerator as 3(x-2). We get
(iv) 3(x-2) / (x-2) = 3.