Question 252614
QUESTION #1: We have the formula
{{{h(t)=125sin(0.157t -pi/2) +125}}}
we want the h(t) = 125. So,
125 =125sin(0.157t -pi/2) + 125
0 = sin(0.157t -pi/2)
sin^-1(0) = (0.157t -pi/2)
{0, PI} = (0.157t -pi/2)
At this point we split and solve:
0 = (0.157t -pi/2) 
pi/2 = .157t
*<FOOTNOTE: .157 ~ pi/20>
t = 10 seconds
pi = (0.157t -pi/2)
3pi/2 = .157t
t = 30 seconds.
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QUESTION #2: approximate the solution to 2cosx+x=0 to the nearest hundredth. 
2cosx + x = 0
2cosx = -x
cosx = -(1/2)x
I don't see any solutions.