Question 252624
Reduce the following fraction to its lowest terms
8a^2m - 32b^2m / 4ax + 8bx 
:
{{{(8a^2m - 32b^2m)/(4ax + 8bx)}}}
Factor
{{{(8m(a^2 - 4b^2))/(4x(a + 2b))}}} = {{{(2m(a^2 - 4b^2))/(x(a + 2b))}}}
Factor the difference of squares
{{{(2m(a-2b)(a+2b))/(x(a + 2b))}}} = {{{(2m(a-2b))/x}}} 
so you are right!!