Question 252607
Here is our formula:
{{{m=(4x)^3+b/a^2+b=(20)}}}
I will assume just the a is squared and not the fraction (a/b).
One problem I notice here is that there are 2 = signs. Secondly, there is an "m". I don't know how that fits in.
I will assume you want the value of x for the following equation:
{{{(4x)^3+b/a^2+b=(20)}}}.
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{{{64x^3 = 20 - b - b/a^2}}}
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{{{x^3 = (20a^2 - ba^2 - b)/64}}}
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{{{x = cube root ((20a^2 -ba^2 - b)/64)}}}
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At this point I don't know if we are done or you want to find a function in terms of and b that produces perfect cube roots for x.