Question 251043
The original problem was:
{{{3 - (a-1)/(a+2) = (a^2-1)/(a+2)}}}
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step 1 multiply by the common denominator of (a+2). We get
{{{3(a+2)-(a-1)=(a^2-1)}}}
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step 2 - distribute and get x^2 on one side = 0.
{{{3a+6-a+1 = a^2 - 1}}}
{{{a^2 -2a -8 = 0}}}
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step 3 - solve for x by factoring:
{{{(x-4)(x+2) = 0}}}
X = 4 and x = -2.
However, look back at our denominator. We have a restriction @ x = -2. we cannot use x = -2, So, the only answer is x = 4.