<PRE><B>Question 252593</B>
here is the original problem:
{{{(3x+6) /  (4x+12)}}} /  {{{(x^2-4) / (x+3)}}}
----
step 1 - factor everything you can and then flip the second fraction and change to multiplication. We get
{{{3(x+2) / 4(x+3)}}} * {{{(x+3) / (x+2)(x-2)}}}
---
step 2 - cancel what you can. We get
{{{3/4 * 1/(x-2)}}}
which is:
3 / (4x-8)</PRE>