Question 31741
3x2 + y2 = 3 ..................(1)
4x2 + 5y2 = 26..................(2)

You can solve it by elimination method (equating the coefficient )

To equate the coefficient of y^2,,,multiply (1) by 5 and we get...
15x2 + 5y2 = 15 ..................(3)

Subtract (2) from (3)..we get

15x2 + 5y2 = 15 
4x2  + 5y2 = 26
-    -       -
------------------
11x2 = -11          (here 5y2 would be eliminated from both equation.)

divide both sides by 11 and we get ...

x2 = -1

now put this value of x either in (1)or in(2),,you get the same value of y2 ,,here I am taking (1)...and we get 

3(-1) + y2 = 3

opening brackets would give ...

-3 + y2 = 3 

add 3 on both sides and we get....

y2 = 6 

Now if you want to  verify you answer ,,,you can put the values of x and y in any of the equation and if you get LHS = RHS,,,this means that you answer is correct..

hope this will help you 

Please feel free to revert back for any further queries.